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Lagrange Multipliers
#12
On second thought it's probably outside of what we need to know so far, considering this is supposed to be an introduction to the lagrange method and second partial derivative test for functions with three variables were nowhere near being mentioned. During the lecture I caught that a condition of using the lagrange method is that both the constraint function and the optimization function need to be differentiable. Is there any way to proof that, or would just actually taking the derivative be enough? Functions in question are: u(x,y) = x^3y^2, g(x,y) = pxX +pyY - m; u(x,y,z) = x^5y^2z^3, g(x,y,z)= pxX + pyY + pzZ - m. Thank you for your replies Smile
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Messages In This Thread
Lagrange Multipliers - by Marksman Bryan - 2012-10-29, 12:41 AM
Lagrange Multipliers - by Rick - 2012-10-29, 12:55 AM
Lagrange Multipliers - by Marksman Bryan - 2012-10-29, 01:26 AM
Lagrange Multipliers - by VerrKol - 2012-10-29, 01:55 AM
Lagrange Multipliers - by Marksman Bryan - 2012-10-29, 02:06 AM
Lagrange Multipliers - by Rick - 2012-10-29, 02:27 AM
Lagrange Multipliers - by VerrKol - 2012-10-29, 04:08 AM
Lagrange Multipliers - by hadriel - 2012-10-29, 04:19 AM
Lagrange Multipliers - by SolicShooter - 2012-11-12, 12:21 PM
Lagrange Multipliers - by Marksman Bryan - 2012-11-12, 06:37 PM
Lagrange Multipliers - by VerrKol - 2012-11-12, 07:01 PM
Lagrange Multipliers - by SolicShooter - 2012-11-12, 07:36 PM
Lagrange Multipliers - by Marksman Bryan - 2012-11-12, 09:06 PM
Lagrange Multipliers - by VerrKol - 2012-11-12, 10:14 PM

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