2012-10-19, 04:04 AM
Stereo Wrote:You can't have 5 in a row, 5 in a column, and 5 in a diagonal without them overlapping in 3 spots - where the row & diagonal meet, where the row & column meet, and where the column & diagonal meet. If you make the 3 overlaps in different places, it's 3 pieces for 6 parts of the solution (and thus cuts 15 to 12) - if you make the 3 overlaps in the same place, it's 1 piece for 3 parts of the solution (and thus cuts 15 to 13).
I meant they'd be parallel so they wouldn't intersect at all. That'd be 15 pieces.

