Can you solve this degeso?

.

25% chance!

Hehe, 33 1/3%.

100%. If you flip 2 coins...

HH
HT
TH
TT

Technically speaking, it's impossible for TT to never occur with a normal coin. For it to never occur, there must be no Tails side at all (or have the coins be biased to always show Heads). Therefore, by eliminating all "Tails" results from the list of possibilities, the only possible combination left is HH. Thus, the probability of obtaining 2 Heads is 100%.

.

-You flip 2 coins
-At least one coin is heads -
Auto 50% chance that the other coin is going to be heads.

Assuming two fair coins, 1/3.

Edit - Note that it says that ONE is heads, not that the first or second coin is heads.

This means that either:
HT
TH
HH

Therefore, 1/3.

Assuming two fair coins, 1/3.

Edit - Note that it says that ONE is heads, not that the first or second coin is heads.

This means that either:
HT
TH
HH

Therefore, 1/3.

ninja

too easy.
next one squid lady.

Nobody has completely gotten the correct answer. Try again.

 This is obviously the answer

but really, I agree with ThatHurts.

Nobody has completely gotten the correct answer. Try again.

Like I said it's easy. The correct answer is 0. You flip two coins. At least one is heads. What is the probability that both are heads?
Silly goose, a coin is not a head. That makes no sense.

i feel like we've been through this before...

P(B|A)= P(BnA)/P(A)

P(HH|at least 1 head) = P(HHnat least 1 head)/P(at least 1 head)

p(HH n at least 1 head ) = P(HH) (since {HH} is contained in {at least 1 head})
P(HH) = 1/4
P(at least 1 head) = 3/4

P(HH)/P(at least 1 head) = (1/4) / (3/4) = 1/3.

2/3 is the answer.

P(B|A)= P(BnA)/P(A)

P(HH|at least 1 head) = P(HHnat least 1 head)/P(at least 1 head)

p(HH n at least 1 head ) = P(HH) (since {HH} is contained in {at least 1 head})
P(HH) = 1/4
P(at least 1 head) = 3/4

P(HH)/P(at least 1 head) = (1/4) / (3/4) = 1/3.

But how do you find out if one of them is heads?

Insufficient information; You never said how many times the coins were flipped. O:

But how do you find out if one of them is heads?

That's completely irrelevant. The questions states that we know. Therefore, we know.

That's completely irrelevant. The questions states that we know. Therefore, we know.

But think of how you would know such an outcome in real life.

You would know that at least one of them is gonna be heads if you had a double-headed coin.
Double-headed coin - Normal coin(Head)
Double-headed coin - Normal coin(Tail)

50%.

But think of how you would know such an outcome in real life.

Easily done~

You and your friend are having a bet. He flips a nickel and a penny and hides them under a bowl while you were turned around. Your friend knows the outcome already, but you don't. Seems really difficult to guess what it landed on though... so he tells you: "At least 1 of the coins was heads." (he has to tell the truth otherwise when he removes the bowl you'll know he cheated you). To win you must guess what each different coin landed on. You want to guess that they're both heads. You're calculating the odds to see how likely you are to guess it right... (with the math from my earlier post) you realize that you have a 1/3 shot of getting it right... so if he offers you 4:1 you should take his bet