2010-01-14, 02:47 AM
Kalovale Wrote:One down. Bacon next. I CHALLENGE YOU!
by "one down" do you mean I'm down, or do you mean I got it right and the question is down?
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Miscellaneous quizzes.
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2010-01-14, 02:47 AM
Kalovale Wrote:One down. Bacon next. I CHALLENGE YOU! by "one down" do you mean I'm down, or do you mean I got it right and the question is down? Horusmaster Wrote:by "one down" do you mean I'm down, or do you mean I got it right and the question is down?You're down, wasn't that your announced last try? I pm'ed you the answer. ![]() Spideyjvc Wrote:Requesting Black elephant
2010-01-14, 02:57 AM
oh god the complexity of the solution....
I bet even Aristotle, Newton, Albert Eistein, Bill Gates, all those smart ppl will not get it. (though I think Bill Gates have highest chance of getting it among those 4)
2010-01-14, 03:21 AM
Spideyjvc Wrote:I enjoyed that thoroughly. And Horus, once you see the Palindrome, you're already on the right way, I just had to make it a bit more complex to avoid googling the whole sequence, the idea of solving it is the same. Only two keys needed, I gave one.
2010-01-14, 04:08 AM
I want to solve this!
If someone else gets it, PM them to tell them they are right! Must not have it spoiled!
2010-01-14, 06:00 AM
More hint updated. The longer you take, the less challenging it gets! Too bad Fiel's Musing is no longer there, it could've been a great reference.
HellenzSin Wrote:then its 127 or im just totally doing it wrongCan I have your reasoning? Don't worry about spoiling because it's wrong. xD EDIT: Actually, 127 fits the bill (at least 2 out of the 3 locks), but is not the next number in question. Hence, PM pl0x.
2010-01-14, 06:12 AM
Hellenz nailed it, wrong answer though. But correct thinking. BACON! I CHALLENGE YOU!!
2010-01-14, 10:49 AM
An old king is about to die and he has no offspring to inherit the crown. So he summons the three wisest men from his kingdom and puts them to a test. He tells them that he is about to put them in a room and have his aide put a hat on each of them. Each hat may or may not have a dot on it, but at least one hat will have a dot. They may not touch the hats, nor communicate in any way. The first one that correctly identifies whether his hat has a dot will become the next king. If he is wrong, or if he breaks the rules, he will be killed. Then he sends all three wise men into the room.
The king then tells his aide to put dotted hats on all three. A few minutes later one of the wise men returns and announces proudly that he has a dot. How did he know? also, an answer to the first riddle could be 79. there are many possible answers that fit that pattern hyperhopper Wrote:An old king is about to die and he has no offspring to inherit the crown. So he summons the three wisest men from his kingdom and puts them to a test. He tells them that he is about to put them in a room and have his aide put a hat on each of them. Each hat may or may not have a dot on it, but at least one hat will have a dot. They may not touch the hats, nor communicate in any way. The first one that correctly identifies whether his hat has a dot will become the next king. If he is wrong, or if he breaks the rules, he will be killed. Then he sends all three wise men into the room.
answer for riddle
And yes, that is why I'm interested in everyone's reasonings behind their answers. And no, if you're looking for a correct answer, I believe I am aware of only 2 solutions as of now. EDIT: Pedro, it would be best if you spoiler that for Bacon, I think he wants a go at it. ![]() EDIT2: Updated quiz #3, invoked from my memory by the above quiz.
2010-01-14, 11:14 AM
hyperhopper Wrote: Doesn't work if the list goes longer though, I simply cut it there for convenience. Good guess though. ![]() EDIT: try my 3rd one, a bit harder than yours.
2010-01-14, 11:16 AM
well, that solution is correct for the numbers you gave. if you give more, then the number of solutions narrows. that is a viable answer. give more numbers if you want less answers
There are 100 coins scattered in a dark room. 90 have heads facing up and 10 have tails up. You cannot distinguish (by feel, etc.) which coins are which. How do you sort the coins into two piles that contain the same number of tails?
2010-01-14, 11:17 AM
hyperhopper Wrote:well, that solution is correct for the numbers you gave. if you give more, then the number of solutions narrows. that is a viable answer. give more numbers if you want less answersReserved post for answer, still thinking. Can I quote your quizzes on the first post? |
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