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+--- Thread: Would anyone happen to be good with linear algebra? (/showthread.php?tid=17627)
Would anyone happen to be good with linear algebra? - DarkPwnage - 2009-10-15
http://people.math.gatech.edu/~geronimo/ma1502/pt3.pdf
On this practice test, could anyone help me with problems 2a and 3?
Would anyone happen to be good with linear algebra? - Dusk - 2009-10-15
Wish I could be of more help. I took that class but I have no idea where to begin. Linear Algebra is so unlike other math ._.
Would anyone happen to be good with linear algebra? - DarkPwnage - 2009-10-15
Yea. My professor uses weird notation too =\.
Like, is f(x,y,z) the same as f( [x y z] ) or
f( [x])?
[y]
[z]
If it weren't for the screwy problems, I could probably do it.
Would anyone happen to be good with linear algebra? - Dusk - 2009-10-15
f(x,y,z) is f on the vector [x,y,z], so yeah f([x,y,z]). I think for 2a you have to set up a matrix X times each vector = the resultant vector they give you and solve for that system of equations.
Would anyone happen to be good with linear algebra? - KajitiSouls - 2009-10-15
Should I bump the math help thread for you guys? >_>
In 2a, you're looking for a transformation matrix T(x) such that T(x) = A*x.
[SPOILER=WARNING: I haven't done linear algebra in a long time, so this is mostly BSing it =P]This is most likely not the proper way to solve the problem, but it solves it nonetheless.
Code:
┌ ┐┌ ┐ ┌ ┐
│ a b c ││ x │ │ m │
│ d e f ││ y │ = │ n │
│ g h i ││ z │ │ o │
└ ┘└ ┘ └ ┘
Inputs:
f(1, 0, 1)
f(1, 2, 1)
f(1, 0,−1)
Equations:
a + c = 1
a + 2b + c = 0
a - c = 0
d + f = 0
d + 2e + f = 1
d - f = 0
g + i = 0
g + 2h + i = 0
g - i = 1
Proposed solution:
┌ ┐┌ ┐ ┌ ┐
│ 1 -1 1 ││ x │ │ m │
½ * │ 0 1 0 ││ y │ = │ n │
│ 1 0 -1 ││ z │ │ o │
└ ┘└ ┘ └ ┘