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+--- Thread: Parametrics...? (/showthread.php?tid=11929)
Parametrics...? - xLeviathan - 2009-06-02
Can someone help me understand this?
This is from my Pre-Calculus Algebra class and this isn't in my book and of course, my professor hasn't gone over it.
![[Image: Parametrics.jpg]](http://img.photobucket.com/albums/v652/DUfire/Parametrics.jpg)
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Parametrics...? - Spaz - 2009-06-02
Putting it into a calculator should be straightforward. Just set it to parametric mode.
Basically, instead of a function taking one argument (x) and transforming it into one value (y) as in y = 5x - 2, it's a function taking one argument (t) and transforming it into two values (x, y).
So for your problem, if t = 0, x = 0^3 = 0 and y = 0 - 2 = -2.
To convert to rectangular, you want to convert it to the form "y = (something)". You know that
y = t - 2
x = t^3
Treat it as a system of equations and solve for y in terms of x.
For part 3, insert the expression containing x in the inequality -3 <= t <= 5 and solve.
Parametrics...? - JoeTang - 2009-06-02
B, D, A
A parametric function is a graph that uses a parameter, t, to set the values for x and y. i.e. x and y are functions of the parameter, t, instead of y being a function of x, etc.
Therefore;
y - 2 = t;
x = t^3
x = (y - 2)^3
x^1/3 - 2 = y
B
t is restricted to -3 <= t <= 5;
therefore, since x = t^3
(-3)^3 <= x <= 5^3
-27 <= x <= 125
D
Graph result is A.
t = -3, y = -5, x = -27;
t = 0, y = -2, x = 0;
t = 5, y = 3, x = 125;
To graph it on a graphing calculator (Some sort of TI-Model should do), select MODE. It should say
Norma | Sci | Eng
Float | 01234...
Radian | Degree
Func | Par | Pol | Seq
You want Par selected, instead of Function.
A pineappleing ninja'd.
Parametrics...? - xLeviathan - 2009-06-03
You both covered the other's missing point, so it's all good.
But the next one is weird.
Okay, x = t^2. -5 <= x <= 2
-5^2 = 25.
2^2 = 4
25 <= x <= 4 ...? Not possible, also not an answer choice.
Parametrics...? - JoeTang - 2009-06-03
xLeviathan Wrote:You both covered the other's missing point, so it's all good.
But the next one is weird.
Okay, x = t^2. -5 <= x <= 2
-5^2 = 25.
2^2 = 4
25 <= x <= 4 ...? Not possible, also not an answer choice.
The bounds are on x, not t?