![]() |
|
Can you solve this degeso? - Printable Version +- Southperry.net (https://www.southperry.net) +-- Forum: Social (https://www.southperry.net/forumdisplay.php?fid=14) +--- Forum: Shenanigans (https://www.southperry.net/forumdisplay.php?fid=51) +--- Thread: Can you solve this degeso? (/showthread.php?tid=35776) Pages:
1
2
|
Can you solve this degeso? - Mute - 2011-01-07 Kunagisa Wrote:But think of how you would know such an outcome in real life. You look and see where the coins fell and what they came up as. Can you solve this degeso? - Kunagisa - 2011-01-07 shouri Wrote:Easily done~ Did you know that a nickel and penny are not made of the same material? But yes this is one way. Can you solve this degeso? - shouri - 2011-01-07 Why does the material matter? 0.o Can you solve this degeso? - Takebacker - 2011-01-07 One of the coins is fake. Always lands on tails. Can you solve this degeso? - xBTAx - 2011-01-07 Kunagisa Wrote: Why would you participate in a game with such a high chance of success? Don't you know that you need to take risks to make miracles happen? Can you solve this degeso? - thinbear - 2011-01-07 http://en.wikipedia.org/wiki/Monty_Hall_problem similar? Can you solve this degeso? - Kunagisa - 2011-01-07 shouri Wrote:Why does the material matter? 0.o Matters more than you think because it creates multiple answers. Can you solve this degeso? - shouri - 2011-01-07 The only way other answers could be created would be if in your original problem HT = TH. Thus the answer would be 1/2 instead of 1/3rd. Which is just arguing sillyness really. Can you solve this degeso? - Milelke - 2011-01-07 Don't overcomplicate things guys. If one coin is already H, the other coin has a 50% chance of being heads or tails. The other coin is heads no matter what, so you already have Hx, x being the other coin, so the chance of them both being heads is 50% because the chance of the unflipped coin being heads is 50%, i think. Can you solve this degeso? - shouri - 2011-01-08 Milelke Wrote:Don't overcomplicate things guys. uh... no. It's only 50% if you know WHICH of the two coins is already a heads. Since you dont, you have three posibilities: HH, HT, TH. So the posibility that both are heads is 1/3rd. Can you solve this degeso? - Takebacker - 2011-01-08 Why does knowing which of them is heads matter when you're already told that one of them is heads? The question is find the probability that both are heads, not find the probability of each possible situation happening. o.o Can you solve this degeso? - shouri - 2011-01-08 When you flip two coins here are all of the possibilities: HH TH HT TT Case1: If you only know that one of them is Heads (but not which one), then you're left with: HH TH HT Thus P(HH)=1/3. Case2: If you know WHICH of the coins is heads (say, the one on the left) you're left with: HH HT Thus P(HH)=1/2. In this problem, however, we're told that 1 of them is heads and not told which one... thus it's the case above and the answer is 1/3. So yeah... the wording makes a difference if you happen to know WHICH is heads, or if you just dont know. Can you solve this degeso? - Kunagisa - 2011-01-08 shouri Wrote:When you flip two coins here are all of the possibilities: But what about the miracle chance of it landing on its side? Can you solve this degeso? - shouri - 2011-01-08 Kunagisa Wrote:But what about the miracle chance of it landing on its side? trololol~ <3 you The coin COULD also spontaneously stop existing... i keep forgetting to account for that... i'm a bad math major T.T |